Tutorials to solve Ratio Questions in Aptitude with Example

Tutorials to solve Ratio Questions in Aptitude

Contents

Ratio Extent Fourth Relative Third Relative Mean Relative Question of Ratio with solved example:

Ratio

Ratio represents the proportion in which a number contains another number. A ratio is represented by a/b or a:b. The duplication or division of every term of a proportion by the same non zero number does not influence the proportion.Subsequently, 3:5 is the same as 6:10 or 9:15 or 12:20 and so on.

Extent

The fairness of two proportions is called extent. As 2:3 = 6:9, we compose, 2:3::6:9 and we can say that 2,3,6,9 are in extent . Here 2 and 9 are called extremes while 3 and 6 are called implies.

In an extent, result of extremes=product of means.

Fourth Relative

if a:b::c:d, then d is known as the fourth relative to a,b and c.

Third Relative

if a:b::c:d, then c is known as the third relative to a and b.

Mean Relative

Mean relative is the middle of a and b.

Question of Ratio with solved example:

Q1. On the off chance that a:b=2:3 and b:c=5:7, discover a:c.

[A] 10:11
[B] 10:21
[C] 21:10
[D] 11:10

Answer – B

Explanation:

We have a/b = 2/3 and b/c = 5/7 
So a/c = (a/b*b/c) = (2/3*5/7) = 10/21 
So its demonstrate that a:c = 10:21

Q2. On the off chance that a:b=2:3 and b:c=5:7, discover a:b:c.

[A] 10:15:21
[B] 10:21:15
[C] 15:10:21
[D] 11:10:21

Answer – A

Explanation:

Here a/b = 2/3 and b/c = 5:7 = 3/5*5:3/5*7 = 3:21/5. 
So a:b=2:3 and b:c=3:21/5 
So a:b:c = 2:3:21/5 = 10:15:21.

Q3. In the event that (5x+3y): (5x-3y) =3:1, then x:y=?

[A] 6:5
[B] 7:8
[C] 8:9
[D] 9:11

Answer – A

Explanation:

Here (5x+3y)/(5x-3y) = 3/1  
=> 5x+3y = 15x-9y
=> 10x = 12y
=> x/y = 12/10 = 6/5 
So x:y =6:5

Q4. In the event that x:y= 5:3 ,then ( 8x-5y) : (8x+5y) = ?

[A] 6:11
[B] 7:11
[C] 8:11
[D] 5:11

Answer – D

Explanation:

Given x/y = 5/3 
Dividing numerator and denominator by y.
(8x-5y)/(8x+5y) = {8(x/y) - 5}/{8(x/y) + 5}
= {8*(5/3)-5}/{8*(5/3)+5}
= (40-15)/(40+15)
= 25/55
= 5/11 
So (8x-5y):(8x+5y)= 5:11

Q5. An aggregate of rs. 391 has been divided between a,b,c in the proportion 1/2 :2/3:3/4 , discover the offer of each..

[A] 102, 136, 153
[B] 112, 114, 123
[C] 114, 117, 129
[D] 122, 134, 123

Answer – A

Explanation:

We have a:b:c=1/2:2/3:3/4= 6:8:9. 
A share = (391*6/23) = 102 rs. 
B offer = (391*8/23) = 136 rs. 
C offer = (391*9/23) = 153 rs.

Q6. A blend contains liquor and water in the proportion 4:3, if 7 liter of water is added to the blend, the proportion of liquor and water gets to be 3:4. Discover the amount of liquor in the blend.

[A] 12 liters
[B] 13 liters
[C] 14 liters
[D] 15 liters

Answer – B

Explanation:

Let the amount of liquor and water be 4x liter and 3x liter separately.
At that point , 4x/3x + 7 = 3/4 
=> 16x = 9x+21 
=> 7x = 21 
so estimation of x is 3 
Amount of liquor in the blend is = 4*3 =12 liters.