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Aptitude – Number system

Times Darpan
Last updated: 2022-03-25 00:28
By Times Darpan 5.6k Views
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Number system

Number system

In Decimal number system, there are ten symbols namely 0,1,2,3,4,5,6,7,8 and 9 called digits. A number is denoted by group of these digits called as numerals.

Contents
Number systemFace ValuePlace ValueTypes of NumbersDivisibility number systemTips on Division number systemDivision AlgorithmSeriesBasic Formulas

Face Value

Face value of a digit in a numeral is value of the digit itself. For example in 321, face value of 1 is 1, face value of 2 is 2 and face value of 3 is 3.

Place Value

Place value of a digit in a numeral is value of the digit multiplied by 10n where n starts from 0. For example in 321:

  • Place value of 1 = 1 x 100 = 1 x 1 = 1
  • Place value of 2 = 2 x 101 = 2 x 10 = 20
  • Place value of 3 = 3 x 102 = 3 x 100 = 300

0th position digit is called unit digit and is the most commonly used topic in aptitude tests.

Types of Numbers

  1. Natural Numbers – n > 0 where n is counting number; [1,2,3…]
  2. Whole Numbers – n ≥ 0 where n is counting number; [0,1,2,3…].

0 is the only whole number which is not a natural number.
Every natural number is a whole number.

  1. Integers – n ≥ 0 or n ≤ 0 where n is counting number;…,-3,-2,-1,0,1,2,3… are integers.
  • Positive Integers – n > 0; [1,2,3…]
  • Negative Integers – n < 0; [-1,-2,-3…]
  • Non-Positive Integers – n ≤ 0; [0,-1,-2,-3…]
  • Non-Negative Integers – n ≥ 0; [0,1,2,3…] number system

0 is neither positive nor negative integer.

  1. Even Numbers – n / 2 = 0 where n is counting number; [0,2,4,…]
  2. Odd Numbers – n / 2 ≠ 0 where n is counting number; [1,3,5,…]
  3. Prime Numbers – Numbers which is divisible by themselves only apart from 1.

1 is not a prime number.

To test a number p to be prime, find a whole number k such that k > √p. Get all prime numbers less than or equal to k and divide p with each of these prime numbers. If no number divides p exactly then p is a prime number otherwise it is not a prime number.

Example: 191 is prime number or not?
Solution:
Step 1 – 14 > √191
Step 2 – Prime numbers less than 14 are 2,3,5,7,11 and 13.
Step 3 – 191 is not divisible by any above prime number.
Result – 191 is a prime number.

Example: 187 is prime number or not?
Solution:
Step 1 – 14 > √187
Step 2 – Prime numbers less than 14 are 2,3,5,7,11 and 13.
Step 3 – 187 is divisible by 11.
Result – 187 is not a prime number.

  1. Composite Numbers – Non-prime numbers > 1. For example, 4,6,8,9 etc.

1 is neither a prime number nor a composite number.
2 is the only even prime number.

  1. Co-Primes Numbers – Two natural numbers are co-primes if their H.C.F. is 1. For example, (2,3), (4,5) are co-primes.

Divisibility number system

Following are tips to check divisibility of numbers. number system

  1. Divisibility by 2 – A number is divisible by 2 if its unit digit is 0,2,4,6 or 8.

Example: 64578 is divisible by 2 or not?
Solution:
Step 1 – Unit digit is 8.
Result – 64578 is divisible by 2.

Example: 64575 is divisible by 2 or not?
Solution:
Step 1 – Unit digit is 5.
Result – 64575 is not divisible by 2.

  1. Divisibility by 3 – A number is divisible by 3 if sum of its digits is completely divisible by 3.

Example: 64578 is divisible by 3 or not?
Solution:
Step 1 – Sum of its digits is 6 + 4 + 5 + 7 + 8 = 30
which is divisible by 3.
Result – 64578 is divisible by 3.

Example: 64576 is divisible by 3 or not?
Solution:
Step 1 – Sum of its digits is 6 + 4 + 5 + 7 + 6 = 28
which is not divisible by 3.
Result – 64576 is not divisible by 3.

  1. Divisibility by 4 – A number is divisible by 4 if number formed using its last two digits is completely divisible by 4.

Example: 64578 is divisible by 4 or not?
Solution:
Step 1 – number formed using its last two digits is 78
which is not divisible by 4.
Result – 64578 is not divisible by 4.

Example: 64580 is divisible by 4 or not?
Solution:
Step 1 – number formed using its last two digits is 80
which is divisible by 4.
Result – 64580 is divisible by 4.

  1. Divisibility by 5 – A number is divisible by 5 if its unit digit is 0 or 5.

Example: 64578 is divisible by 5 or not?
Solution:
Step 1 – Unit digit is 8.
Result – 64578 is not divisible by 5.

Example: 64575 is divisible by 5 or not?
Solution:
Step 1 – Unit digit is 5.
Result – 64575 is divisible by 5.

  1. Divisibility by 6 – A number is divisible by 6 if the number is divisible by both 2 and 3. number system

Example: 64578 is divisible by 6 or not?
Solution:
Step 1 – Unit digit is 8. Number is divisible by 2.
Step 2 – Sum of its digits is 6 + 4 + 5 + 7 + 8 = 30
which is divisible by 3.
Result – 64578 is divisible by 6.

Example: 64576 is divisible by 6 or not?
Solution:
Step 1 – Unit digit is 8. Number is divisible by 2.
Step 2 – Sum of its digits is 6 + 4 + 5 + 7 + 6 = 28
which is not divisible by 3.
Result – 64576 is not divisible by 6.

  1. Divisibility by 8 – A number is divisible by 8 if number formed using its last three digits is completely divisible by 8.

Example: 64578 is divisible by 8 or not?
Solution:
Step 1 – number formed using its last three digits is 578
which is not divisible by 8.
Result – 64578 is not divisible by 8.

Example: 64576 is divisible by 8 or not?
Solution:
Step 1 – number formed using its last three digits is 576
which is divisible by 8.
Result – 64576 is divisible by 8.

  1. Divisibility by 9 – A number is divisible by 9 if sum of its digits is completely divisible by 9.

Example: 64579 is divisible by 9 or not?
Solution:
Step 1 – Sum of its digits is 6 + 4 + 5 + 7 + 9 = 31
which is not divisible by 9.
Result – 64579 is not divisible by 9.

Example: 64575 is divisible by 9 or not?
Solution:
Step 1 – Sum of its digits is 6 + 4 + 5 + 7 + 5 = 27
which is divisible by 9.
Result – 64575 is divisible by 9.

  1. Divisibility by 10 – A number is divisible by 10 if its unit digit is 0.

Example: 64575 is divisible by 10 or not?
Solution:
Step 1 – Unit digit is 5.
Result – 64578 is not divisible by 10.

Example: 64570 is divisible by 10 or not?
Solution:
Step 1 – Unit digit is 0.
Result – 64570 is divisible by 10.

  1. Divisibility by 11 – A number is divisible by 11 if difference between sum of digits at odd places and sum of digits at even places is either 0 or is divisible by 11.

Example: 64575 is divisible by 11 or not?
Solution:
Step 1 – difference between sum of digits at odd places
and sum of digits at even places = (6+5+5) – (4+7) = 5
which is not divisible by 11.
Result – 64575 is not divisible by 11.

Example: 64075 is divisible by 11 or not?
Solution:
Step 1 – difference between sum of digits at odd places
and sum of digits at even places = (6+0+5) – (4+7) = 0.
Result – 64075 is divisible by 11.

Tips on Division number system

  1. If a number n is divisible by two co-primes numbers a, b then n is divisible by ab.
  2. (a-b) always divides (an – bn) if n is a natural number.
  3. (a+b) always divides (an – bn) if n is an even number.
  4. (a+b) always divides (an + bn) if n is an odd number. number system

Division Algorithm

When a number is divided by another number then

Dividend = (Divisor x Quotient) + Reminder

Series

Following are formulaes for basic number series:

  1. (1+2+3+…+n) = (1/2)n(n+1)
  2. (12+22+32+…+n2) = (1/6)n(n+1)(2n+1)
  3. (13+23+33+…+n3) = (1/4)n2(n+1)2

Basic Formulas

These are the basic formulae:

(a + b)2 = a2 + b2 + 2ab

(a – b)2 = a2 + b2 – 2ab

(a + b)2 – (a – b)2 = 4ab

(a + b)2 + (a – b)2 = 2(a2 + b2)

(a2 – b2) = (a + b)(a – b)

(a + b + c)2 = a2 + b2 + c2 + 2(ab + bc + ca)

(a3 + b3) = (a + b)(a2 – ab + b2)

(a3 – b3) = (a – b)(a2 + ab + b2)

(a3 + b3 + c3 – 3abc) = (a + b + c)(a2 + b2 + c2 – ab – bc – ca)

TAGGED:Number system
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1 Comment 1 Comment
  • Ashu S. says:
    2021-04-30 at 08:37

    Why U Are Not Publishing NCERT Solution?? plz publish ??

    Reply

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